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For an integer result, convert the number to text, reverse the digits with slicing, and convert back: int(str(n)[::-1]). Use an arithmetic loop instead if string conversion is not allowed, and return a string if leading zeroes must remain visible.
Reverse an integer with string slicing
For a non-negative integer, this is the shortest approach:
def reverse_number(n: int) -> int:
return int(str(n)[::-1])
print(reverse_number(12345)) # 54321
str(n) creates the digit text, [::-1] reads it backward, and int(...) converts the result back to an integer. Python’s numeric type reference distinguishes integers from floats; this recipe is for integers, not decimal values.
Handle negative integers
Reverse the magnitude and restore the sign separately, so the minus sign is not treated as a digit:
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def reverse_number(n: int) -> int:
sign = -1 if n < 0 else 1
return sign * int(str(abs(n))[::-1])
Choose whether zeroes should be preserved
An integer cannot retain leading zeroes. Reversing 1200 and converting the result to an integer produces 21, not 0021. If the reversed digits are meant to be displayed with zeroes intact, return text instead:
def reverse_digits_text(n: int) -> str:
sign = "-" if n < 0 else ""
return sign + str(abs(n))[::-1]
print(reverse_digits_text(1200)) # '0021'
Reverse digits with arithmetic
If an exercise requires a loop or forbids converting the number to a string, extract one digit at a time with remainder and floor division:
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def reverse_number_arithmetic(n: int) -> int:
sign = -1 if n < 0 else 1
n = abs(n)
reversed_number = 0
while n:
digit = n % 10
reversed_number = reversed_number * 10 + digit
n //= 10
return sign * reversed_number
print(reverse_number_arithmetic(1234)) # 4321
Each loop iteration extracts the last digit with % 10, shifts the accumulated answer one decimal place by multiplying by 10, then removes the processed digit with // 10. The Python numeric-operator reference defines divmod(x, y) as (x // y, x % y) and notes that floor division rounds toward minus infinity. Here the input is made non-negative first, so these operations process ordinary decimal digits. For input 0, the loop is skipped and the initialized result remains 0.
Which method should you use?
| Need | Use | Result for 1200 |
|---|---|---|
| Shortest, clearest integer solution | String slicing with int(...) |
21 |
| Arithmetic-only digit processing | Remainder and floor-division loop | 21 |
| Preserve all reversed digits, including leading zeroes | Return reversed text | '0021' |
Both integer-returning approaches reverse the digits of non-negative integers; the arithmetic version is useful when the method itself is part of the exercise. Define negative-number handling explicitly if your assignment specifies a different convention.
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What about floating-point numbers?
Do not apply the integer recipe to a float without deciding what reversing a decimal means. The decimal point is not a digit, and Python’s numeric type reference states that converting a float to int truncates its fractional part. For example, converting 12.34 to int first discards the fraction; that is not the same as reversing the digits of the original decimal text. Specify whether the decimal point, sign, and zero padding should be preserved before implementing a float-specific rule.
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