Use a slice with an omitted start and an exclusive end bound one position before the end:
s = "Python"
shorter = s[:-1]
print(shorter) # Pythos[:-1] returns every indexed string element except the final one. It does not modify s; Python strings are immutable, so keep the returned value or assign it back with s = s[:-1].
The direct solution: s[:-1]
Python slice notation is sequence[start:stop]. The start is included, while the stop is excluded. Omitting start means “begin at the first element,” and -1 identifies the position immediately before the final element when used as the exclusive stop. Together, s[:-1] means “from the beginning up to, but not including, the last indexed element.”
name = "Ada Lovelace"
without_last = name[:-1]
print(without_last) # Ada LovacThe expression creates a new string value. If you need the variable itself to refer to the shortened value, reassign it:
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s = "Python"
s = s[:-1]
print(s) # PythoThe Python Software Foundation’s tutorial describes strings as immutable: their contents cannot be changed in place. A slice therefore returns a result rather than editing the original object.
How the slice bounds work
The built-in types reference defines a slice as the sequence elements whose indexes satisfy i <= k < j. The right-hand bound is exclusive, which is why the character at index -1 is left out.
s = "Python"
print(s[0]) # P
print(s[-1]) # n
print(s[:-1]) # PythoNegative indexes count backward from the end. Index -1 is the final element, -2 is the one before it, and so on. Because the stop value is excluded, stopping at -1 retains everything before the final element.
Empty and one-character strings
The same expression safely handles short input:
print(""[:-1]) # ""
print("x"[:-1]) # ""An empty string has no element to remove, and a one-character string has no elements before its final character. In both cases the result is an empty string; Python adjusts the slice bounds instead of raising an index error.
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Removing exactly one character versus trimming text
Choose the operation that matches your requirement. These methods are not interchangeable:
| Requirement | Use | Behavior |
|---|---|---|
| Remove exactly the final indexed element, whatever it is | s[:-1] |
Returns all elements except the last one. |
| Remove a known literal suffix | s.removesuffix(suffix) |
Removes that matching suffix string, not an arbitrary final character. |
| Trim a trailing run made from selected characters | s.rstrip(chars) |
Continues removing characters from the end while they belong to the supplied character set. |
| Trim trailing whitespace | s.rstrip() |
Removes trailing whitespace, potentially more than one character. |
Known suffixes
If the requirement is “remove .csv when it is present,” use the suffix-aware method instead of deleting one character:
filename = "report.csv"
print(filename.removesuffix(".csv")) # reportThis expresses the condition directly: a nonmatching suffix is left unchanged. It solves a different problem from s[:-1].
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rstrip(chars) treats its argument as a set of characters and removes a trailing run. For example:
value = "hello!!!"
print(value.rstrip("!")) # helloIt is unsuitable when exactly one final element must be removed, because several matching characters may be stripped.
Strings are immutable: use or assign the result
This code does not shorten the original object:
s = "Python"
result = s[:-1]
print(s) # Python
print(result) # PythoUse one of these patterns depending on your intent:
- Keep both values: assign the slice to a new variable.
- Replace the variable: write
s = s[:-1]. - Pass it directly: call a function with
s[:-1]without storing it.
def label_without_last(label):
return label[:-1]
print(label_without_last("Draft?")) # DraftUnicode and the meaning of “character”
Python indexes a string by string elements (Unicode code points), not necessarily by the visible symbols a person perceives as one character. A displayed symbol can consist of multiple code points, such as a base letter followed by a combining mark or an emoji sequence joined from several code points.
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Consequently, s[:-1] removes one indexed code point. It may leave a combining mark, variation selector, or part of a multi-code-point emoji sequence behind, producing a result that looks surprising. The ordinary slice remains correct for code-point-level processing, but it is not a general “remove one visible symbol” operation.
If your requirement is grapheme-cluster-aware editing—removing one user-perceived symbol—use Unicode grapheme segmentation and a library designed for that purpose. The basic slicing rule alone does not provide that behavior.
Practical examples
Removing punctuation added by formatting
line = "Status: OK;"
clean = line[:-1]
print(clean) # Status: OKUse this only when the final element is known to be the punctuation you intend to remove. If the text may or may not end in a semicolon, test first or use a suffix operation:
line = "Status: OK;"
if line.endswith(";"):
line = line.removesuffix(";")Processing a list of strings
values = ["alpha!", "beta!", "gamma!"]
trimmed = [value[:-1] for value in values]
print(trimmed) # ['alpha', 'beta', 'gamma']Each slice returns a new string; the original list elements remain unchanged.
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def test_remove_last_character():
assert "Python"[:-1] == "Pytho"
assert "x"[:-1] == ""
assert ""[:-1] == ""Common mistakes and fixes
Using s[-1] instead of a slice
s[-1] returns only the final element. To return everything except that element, use s[:-1].
Expecting the original string to change
Assign the result back: s = s[:-1]. Without assignment, the original reference still points to the unchanged string.
Calling rstrip() for an exact one-element removal
rstrip() can remove a run of whitespace or selected characters. Replace it with s[:-1] when the requirement is exactly one final indexed element.
Removing a suffix without checking what it is
s[:-1] removes the final element even when it is not the suffix you expected. Use removesuffix("...") when the literal suffix must match.
Unexpected results with emoji or combining marks
Inspect the string’s code points and clarify whether your application needs code-point slicing or grapheme-aware editing. Do not assume one visible symbol always equals one Python index.
Independent reader supportYour contribution helps us test, update, and keep practical guides available for everyone.Performance and reliability notes
Slicing constructs a new string containing the retained elements. For a one-character removal this is the idiomatic, readable operation. In a loop that repeatedly shortens a very large string, repeatedly copying the remaining text can do unnecessary work; consider collecting pieces and joining them once, or use a data structure suited to repeated edits. For ordinary labels, lines, filenames, and tokens, s[:-1] is the simplest reliable choice.
Because the operation does not mutate shared strings, it is safe to use when the original value is needed elsewhere. Validate the semantic requirement—arbitrary final element, known suffix, trailing character set, or visible Unicode symbol—before choosing the syntax.
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Decision checklist
- Need all but the final indexed element? Use
s[:-1]. - Need to remove a specific literal ending? Use
removesuffix(). - Need to trim trailing whitespace or a character set? Use
rstrip(). - Need to remove one visible Unicode symbol? Use grapheme segmentation rather than assuming one index equals one symbol.
- Need the variable shortened? Reassign the slice result.
Frequently Asked Questions
Can I use a variable instead of a literal string in the slice?
Yes. Any string expression can appear before [:-1], including a function return, dictionary value, or formatted variable, as long as the value supports string slicing.
What does a negative step change?
A negative step reverses traversal and is a different operation. For removing only the final element while preserving order, leave the step out and use s[:-1].
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